Optimal. Leaf size=295 \[ -\frac{b \text{PolyLog}\left (2,1-\frac{2}{1-c x}\right ) \left (a+b \tanh ^{-1}(c x)\right )}{d^2}+\frac{b \text{PolyLog}\left (2,\frac{2}{1-c x}-1\right ) \left (a+b \tanh ^{-1}(c x)\right )}{d^2}-\frac{b \text{PolyLog}\left (2,1-\frac{2}{c x+1}\right ) \left (a+b \tanh ^{-1}(c x)\right )}{d^2}+\frac{b^2 \text{PolyLog}\left (3,1-\frac{2}{1-c x}\right )}{2 d^2}-\frac{b^2 \text{PolyLog}\left (3,\frac{2}{1-c x}-1\right )}{2 d^2}-\frac{b^2 \text{PolyLog}\left (3,1-\frac{2}{c x+1}\right )}{2 d^2}+\frac{b \left (a+b \tanh ^{-1}(c x)\right )}{d^2 (c x+1)}+\frac{\left (a+b \tanh ^{-1}(c x)\right )^2}{d^2 (c x+1)}-\frac{\left (a+b \tanh ^{-1}(c x)\right )^2}{2 d^2}+\frac{2 \tanh ^{-1}\left (1-\frac{2}{1-c x}\right ) \left (a+b \tanh ^{-1}(c x)\right )^2}{d^2}+\frac{\log \left (\frac{2}{c x+1}\right ) \left (a+b \tanh ^{-1}(c x)\right )^2}{d^2}+\frac{b^2}{2 d^2 (c x+1)}-\frac{b^2 \tanh ^{-1}(c x)}{2 d^2} \]
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Rubi [A] time = 0.640484, antiderivative size = 295, normalized size of antiderivative = 1., number of steps used = 19, number of rules used = 13, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.591, Rules used = {5940, 5914, 6052, 5948, 6058, 6610, 5928, 5926, 627, 44, 207, 5918, 6056} \[ -\frac{b \text{PolyLog}\left (2,1-\frac{2}{1-c x}\right ) \left (a+b \tanh ^{-1}(c x)\right )}{d^2}+\frac{b \text{PolyLog}\left (2,\frac{2}{1-c x}-1\right ) \left (a+b \tanh ^{-1}(c x)\right )}{d^2}-\frac{b \text{PolyLog}\left (2,1-\frac{2}{c x+1}\right ) \left (a+b \tanh ^{-1}(c x)\right )}{d^2}+\frac{b^2 \text{PolyLog}\left (3,1-\frac{2}{1-c x}\right )}{2 d^2}-\frac{b^2 \text{PolyLog}\left (3,\frac{2}{1-c x}-1\right )}{2 d^2}-\frac{b^2 \text{PolyLog}\left (3,1-\frac{2}{c x+1}\right )}{2 d^2}+\frac{b \left (a+b \tanh ^{-1}(c x)\right )}{d^2 (c x+1)}+\frac{\left (a+b \tanh ^{-1}(c x)\right )^2}{d^2 (c x+1)}-\frac{\left (a+b \tanh ^{-1}(c x)\right )^2}{2 d^2}+\frac{2 \tanh ^{-1}\left (1-\frac{2}{1-c x}\right ) \left (a+b \tanh ^{-1}(c x)\right )^2}{d^2}+\frac{\log \left (\frac{2}{c x+1}\right ) \left (a+b \tanh ^{-1}(c x)\right )^2}{d^2}+\frac{b^2}{2 d^2 (c x+1)}-\frac{b^2 \tanh ^{-1}(c x)}{2 d^2} \]
Antiderivative was successfully verified.
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Rule 5940
Rule 5914
Rule 6052
Rule 5948
Rule 6058
Rule 6610
Rule 5928
Rule 5926
Rule 627
Rule 44
Rule 207
Rule 5918
Rule 6056
Rubi steps
\begin{align*} \int \frac{\left (a+b \tanh ^{-1}(c x)\right )^2}{x (d+c d x)^2} \, dx &=\int \left (\frac{\left (a+b \tanh ^{-1}(c x)\right )^2}{d^2 x}-\frac{c \left (a+b \tanh ^{-1}(c x)\right )^2}{d^2 (1+c x)^2}-\frac{c \left (a+b \tanh ^{-1}(c x)\right )^2}{d^2 (1+c x)}\right ) \, dx\\ &=\frac{\int \frac{\left (a+b \tanh ^{-1}(c x)\right )^2}{x} \, dx}{d^2}-\frac{c \int \frac{\left (a+b \tanh ^{-1}(c x)\right )^2}{(1+c x)^2} \, dx}{d^2}-\frac{c \int \frac{\left (a+b \tanh ^{-1}(c x)\right )^2}{1+c x} \, dx}{d^2}\\ &=\frac{\left (a+b \tanh ^{-1}(c x)\right )^2}{d^2 (1+c x)}+\frac{2 \left (a+b \tanh ^{-1}(c x)\right )^2 \tanh ^{-1}\left (1-\frac{2}{1-c x}\right )}{d^2}+\frac{\left (a+b \tanh ^{-1}(c x)\right )^2 \log \left (\frac{2}{1+c x}\right )}{d^2}-\frac{(2 b c) \int \left (\frac{a+b \tanh ^{-1}(c x)}{2 (1+c x)^2}-\frac{a+b \tanh ^{-1}(c x)}{2 \left (-1+c^2 x^2\right )}\right ) \, dx}{d^2}-\frac{(2 b c) \int \frac{\left (a+b \tanh ^{-1}(c x)\right ) \log \left (\frac{2}{1+c x}\right )}{1-c^2 x^2} \, dx}{d^2}-\frac{(4 b c) \int \frac{\left (a+b \tanh ^{-1}(c x)\right ) \tanh ^{-1}\left (1-\frac{2}{1-c x}\right )}{1-c^2 x^2} \, dx}{d^2}\\ &=\frac{\left (a+b \tanh ^{-1}(c x)\right )^2}{d^2 (1+c x)}+\frac{2 \left (a+b \tanh ^{-1}(c x)\right )^2 \tanh ^{-1}\left (1-\frac{2}{1-c x}\right )}{d^2}+\frac{\left (a+b \tanh ^{-1}(c x)\right )^2 \log \left (\frac{2}{1+c x}\right )}{d^2}-\frac{b \left (a+b \tanh ^{-1}(c x)\right ) \text{Li}_2\left (1-\frac{2}{1+c x}\right )}{d^2}-\frac{(b c) \int \frac{a+b \tanh ^{-1}(c x)}{(1+c x)^2} \, dx}{d^2}+\frac{(b c) \int \frac{a+b \tanh ^{-1}(c x)}{-1+c^2 x^2} \, dx}{d^2}+\frac{(2 b c) \int \frac{\left (a+b \tanh ^{-1}(c x)\right ) \log \left (\frac{2}{1-c x}\right )}{1-c^2 x^2} \, dx}{d^2}-\frac{(2 b c) \int \frac{\left (a+b \tanh ^{-1}(c x)\right ) \log \left (2-\frac{2}{1-c x}\right )}{1-c^2 x^2} \, dx}{d^2}+\frac{\left (b^2 c\right ) \int \frac{\text{Li}_2\left (1-\frac{2}{1+c x}\right )}{1-c^2 x^2} \, dx}{d^2}\\ &=\frac{b \left (a+b \tanh ^{-1}(c x)\right )}{d^2 (1+c x)}-\frac{\left (a+b \tanh ^{-1}(c x)\right )^2}{2 d^2}+\frac{\left (a+b \tanh ^{-1}(c x)\right )^2}{d^2 (1+c x)}+\frac{2 \left (a+b \tanh ^{-1}(c x)\right )^2 \tanh ^{-1}\left (1-\frac{2}{1-c x}\right )}{d^2}+\frac{\left (a+b \tanh ^{-1}(c x)\right )^2 \log \left (\frac{2}{1+c x}\right )}{d^2}-\frac{b \left (a+b \tanh ^{-1}(c x)\right ) \text{Li}_2\left (1-\frac{2}{1-c x}\right )}{d^2}+\frac{b \left (a+b \tanh ^{-1}(c x)\right ) \text{Li}_2\left (-1+\frac{2}{1-c x}\right )}{d^2}-\frac{b \left (a+b \tanh ^{-1}(c x)\right ) \text{Li}_2\left (1-\frac{2}{1+c x}\right )}{d^2}-\frac{b^2 \text{Li}_3\left (1-\frac{2}{1+c x}\right )}{2 d^2}-\frac{\left (b^2 c\right ) \int \frac{1}{(1+c x) \left (1-c^2 x^2\right )} \, dx}{d^2}+\frac{\left (b^2 c\right ) \int \frac{\text{Li}_2\left (1-\frac{2}{1-c x}\right )}{1-c^2 x^2} \, dx}{d^2}-\frac{\left (b^2 c\right ) \int \frac{\text{Li}_2\left (-1+\frac{2}{1-c x}\right )}{1-c^2 x^2} \, dx}{d^2}\\ &=\frac{b \left (a+b \tanh ^{-1}(c x)\right )}{d^2 (1+c x)}-\frac{\left (a+b \tanh ^{-1}(c x)\right )^2}{2 d^2}+\frac{\left (a+b \tanh ^{-1}(c x)\right )^2}{d^2 (1+c x)}+\frac{2 \left (a+b \tanh ^{-1}(c x)\right )^2 \tanh ^{-1}\left (1-\frac{2}{1-c x}\right )}{d^2}+\frac{\left (a+b \tanh ^{-1}(c x)\right )^2 \log \left (\frac{2}{1+c x}\right )}{d^2}-\frac{b \left (a+b \tanh ^{-1}(c x)\right ) \text{Li}_2\left (1-\frac{2}{1-c x}\right )}{d^2}+\frac{b \left (a+b \tanh ^{-1}(c x)\right ) \text{Li}_2\left (-1+\frac{2}{1-c x}\right )}{d^2}-\frac{b \left (a+b \tanh ^{-1}(c x)\right ) \text{Li}_2\left (1-\frac{2}{1+c x}\right )}{d^2}+\frac{b^2 \text{Li}_3\left (1-\frac{2}{1-c x}\right )}{2 d^2}-\frac{b^2 \text{Li}_3\left (-1+\frac{2}{1-c x}\right )}{2 d^2}-\frac{b^2 \text{Li}_3\left (1-\frac{2}{1+c x}\right )}{2 d^2}-\frac{\left (b^2 c\right ) \int \frac{1}{(1-c x) (1+c x)^2} \, dx}{d^2}\\ &=\frac{b \left (a+b \tanh ^{-1}(c x)\right )}{d^2 (1+c x)}-\frac{\left (a+b \tanh ^{-1}(c x)\right )^2}{2 d^2}+\frac{\left (a+b \tanh ^{-1}(c x)\right )^2}{d^2 (1+c x)}+\frac{2 \left (a+b \tanh ^{-1}(c x)\right )^2 \tanh ^{-1}\left (1-\frac{2}{1-c x}\right )}{d^2}+\frac{\left (a+b \tanh ^{-1}(c x)\right )^2 \log \left (\frac{2}{1+c x}\right )}{d^2}-\frac{b \left (a+b \tanh ^{-1}(c x)\right ) \text{Li}_2\left (1-\frac{2}{1-c x}\right )}{d^2}+\frac{b \left (a+b \tanh ^{-1}(c x)\right ) \text{Li}_2\left (-1+\frac{2}{1-c x}\right )}{d^2}-\frac{b \left (a+b \tanh ^{-1}(c x)\right ) \text{Li}_2\left (1-\frac{2}{1+c x}\right )}{d^2}+\frac{b^2 \text{Li}_3\left (1-\frac{2}{1-c x}\right )}{2 d^2}-\frac{b^2 \text{Li}_3\left (-1+\frac{2}{1-c x}\right )}{2 d^2}-\frac{b^2 \text{Li}_3\left (1-\frac{2}{1+c x}\right )}{2 d^2}-\frac{\left (b^2 c\right ) \int \left (\frac{1}{2 (1+c x)^2}-\frac{1}{2 \left (-1+c^2 x^2\right )}\right ) \, dx}{d^2}\\ &=\frac{b^2}{2 d^2 (1+c x)}+\frac{b \left (a+b \tanh ^{-1}(c x)\right )}{d^2 (1+c x)}-\frac{\left (a+b \tanh ^{-1}(c x)\right )^2}{2 d^2}+\frac{\left (a+b \tanh ^{-1}(c x)\right )^2}{d^2 (1+c x)}+\frac{2 \left (a+b \tanh ^{-1}(c x)\right )^2 \tanh ^{-1}\left (1-\frac{2}{1-c x}\right )}{d^2}+\frac{\left (a+b \tanh ^{-1}(c x)\right )^2 \log \left (\frac{2}{1+c x}\right )}{d^2}-\frac{b \left (a+b \tanh ^{-1}(c x)\right ) \text{Li}_2\left (1-\frac{2}{1-c x}\right )}{d^2}+\frac{b \left (a+b \tanh ^{-1}(c x)\right ) \text{Li}_2\left (-1+\frac{2}{1-c x}\right )}{d^2}-\frac{b \left (a+b \tanh ^{-1}(c x)\right ) \text{Li}_2\left (1-\frac{2}{1+c x}\right )}{d^2}+\frac{b^2 \text{Li}_3\left (1-\frac{2}{1-c x}\right )}{2 d^2}-\frac{b^2 \text{Li}_3\left (-1+\frac{2}{1-c x}\right )}{2 d^2}-\frac{b^2 \text{Li}_3\left (1-\frac{2}{1+c x}\right )}{2 d^2}+\frac{\left (b^2 c\right ) \int \frac{1}{-1+c^2 x^2} \, dx}{2 d^2}\\ &=\frac{b^2}{2 d^2 (1+c x)}-\frac{b^2 \tanh ^{-1}(c x)}{2 d^2}+\frac{b \left (a+b \tanh ^{-1}(c x)\right )}{d^2 (1+c x)}-\frac{\left (a+b \tanh ^{-1}(c x)\right )^2}{2 d^2}+\frac{\left (a+b \tanh ^{-1}(c x)\right )^2}{d^2 (1+c x)}+\frac{2 \left (a+b \tanh ^{-1}(c x)\right )^2 \tanh ^{-1}\left (1-\frac{2}{1-c x}\right )}{d^2}+\frac{\left (a+b \tanh ^{-1}(c x)\right )^2 \log \left (\frac{2}{1+c x}\right )}{d^2}-\frac{b \left (a+b \tanh ^{-1}(c x)\right ) \text{Li}_2\left (1-\frac{2}{1-c x}\right )}{d^2}+\frac{b \left (a+b \tanh ^{-1}(c x)\right ) \text{Li}_2\left (-1+\frac{2}{1-c x}\right )}{d^2}-\frac{b \left (a+b \tanh ^{-1}(c x)\right ) \text{Li}_2\left (1-\frac{2}{1+c x}\right )}{d^2}+\frac{b^2 \text{Li}_3\left (1-\frac{2}{1-c x}\right )}{2 d^2}-\frac{b^2 \text{Li}_3\left (-1+\frac{2}{1-c x}\right )}{2 d^2}-\frac{b^2 \text{Li}_3\left (1-\frac{2}{1+c x}\right )}{2 d^2}\\ \end{align*}
Mathematica [C] time = 0.847599, size = 254, normalized size = 0.86 \[ \frac{12 a b \left (-2 \text{PolyLog}\left (2,e^{-2 \tanh ^{-1}(c x)}\right )-\sinh \left (2 \tanh ^{-1}(c x)\right )+\cosh \left (2 \tanh ^{-1}(c x)\right )+2 \tanh ^{-1}(c x) \left (2 \log \left (1-e^{-2 \tanh ^{-1}(c x)}\right )-\sinh \left (2 \tanh ^{-1}(c x)\right )+\cosh \left (2 \tanh ^{-1}(c x)\right )\right )\right )+b^2 \left (24 \tanh ^{-1}(c x) \text{PolyLog}\left (2,e^{2 \tanh ^{-1}(c x)}\right )-12 \text{PolyLog}\left (3,e^{2 \tanh ^{-1}(c x)}\right )-16 \tanh ^{-1}(c x)^3+24 \tanh ^{-1}(c x)^2 \log \left (1-e^{2 \tanh ^{-1}(c x)}\right )-12 \tanh ^{-1}(c x)^2 \sinh \left (2 \tanh ^{-1}(c x)\right )-12 \tanh ^{-1}(c x) \sinh \left (2 \tanh ^{-1}(c x)\right )-6 \sinh \left (2 \tanh ^{-1}(c x)\right )+12 \tanh ^{-1}(c x)^2 \cosh \left (2 \tanh ^{-1}(c x)\right )+12 \tanh ^{-1}(c x) \cosh \left (2 \tanh ^{-1}(c x)\right )+6 \cosh \left (2 \tanh ^{-1}(c x)\right )+i \pi ^3\right )+\frac{24 a^2}{c x+1}+24 a^2 \log (c x)-24 a^2 \log (c x+1)}{24 d^2} \]
Warning: Unable to verify antiderivative.
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Maple [C] time = 0.339, size = 1566, normalized size = 5.3 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} a^{2}{\left (\frac{1}{c d^{2} x + d^{2}} - \frac{\log \left (c x + 1\right )}{d^{2}} + \frac{\log \left (x\right )}{d^{2}}\right )} + \frac{{\left (b^{2} -{\left (b^{2} c x + b^{2}\right )} \log \left (c x + 1\right )\right )} \log \left (-c x + 1\right )^{2}}{4 \,{\left (c d^{2} x + d^{2}\right )}} + \int \frac{{\left (b^{2} c x - b^{2}\right )} \log \left (c x + 1\right )^{2} + 4 \,{\left (a b c x - a b\right )} \log \left (c x + 1\right ) - 2 \,{\left (b^{2} c^{2} x^{2} - 2 \, a b +{\left (2 \, a b c + b^{2} c\right )} x -{\left (b^{2} c^{3} x^{3} + 2 \, b^{2} c^{2} x^{2} + b^{2}\right )} \log \left (c x + 1\right )\right )} \log \left (-c x + 1\right )}{4 \,{\left (c^{3} d^{2} x^{4} + c^{2} d^{2} x^{3} - c d^{2} x^{2} - d^{2} x\right )}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{b^{2} \operatorname{artanh}\left (c x\right )^{2} + 2 \, a b \operatorname{artanh}\left (c x\right ) + a^{2}}{c^{2} d^{2} x^{3} + 2 \, c d^{2} x^{2} + d^{2} x}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{\int \frac{a^{2}}{c^{2} x^{3} + 2 c x^{2} + x}\, dx + \int \frac{b^{2} \operatorname{atanh}^{2}{\left (c x \right )}}{c^{2} x^{3} + 2 c x^{2} + x}\, dx + \int \frac{2 a b \operatorname{atanh}{\left (c x \right )}}{c^{2} x^{3} + 2 c x^{2} + x}\, dx}{d^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (b \operatorname{artanh}\left (c x\right ) + a\right )}^{2}}{{\left (c d x + d\right )}^{2} x}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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